![]() ![]() One volt is the potential difference when one coulomb of charge transfers one joule of energy. If by 'current is opposite to emf' you mean that conventional current is flowing into the positive terminal of the source, then ask yourself how this can happen. charge ( Q ) is measured in coulombs (C) 28,261 3 Sumit Aich said: Is the work done by a constant voltage source positive or negative when current is opposite to emf This sounds like a homework question.potential difference ( V ) is measured in volts (V).The force that we think of when we try to lift that parallel push-pull boat anchor is the mass times the acceleration of gravity, which happens to be 9.8 meters per second squared. The potential difference can be calculated using the equation: It turns out that a kilogram is a unit of mass. When a charge moves through a potential difference, electrical work is done and energy transferred. We can model this circuit quite easily by combining the voltmeter (modeled as a resistor) in parallel with one of the resistors: Reff RVR RV + R (10k)(1k) (10k) + (1k) 10 11k 0.91k The sum of the voltage drops across the effective resistor and the other resistor. Length of wire is measured using a metre ruler Energy, voltage and charge Figure 20.4.5: When using a voltmeter, the circuit is modified. Circuit with a 1.5 V cell, ammeter, voltmeter and thin resistence wire connected in parallel. Potential difference is also known as voltage and is measured in volts (V). To measure the potential difference across a component, a voltmeter must be placed in parallel with that component in order to measure the difference in energy from one side of the component to the other. A potential difference of 1 volt means that 1 joule of work is done per coulomb of charge. Potential difference (or voltage) is a measure of energy, per unit of charge, transferred between two points in a circuit. This states that the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. ![]()
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